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import os
import re
import sys
from typing import List, Optional
from pip._internal.locations import site_packages, user_site
from pip._internal.utils.virtualenv import (
running_under_virtualenv,
virtualenv_no_global,
)
__all__ = [
"egg_link_path_from_sys_path",
"egg_link_path_from_location",
]
def _egg_link_names(raw_name: str) -> List[str]:
"""
Convert a Name metadata value to a .egg-link name, by applying
the same substitution as pkg_resources's safe_name function.
Note: we cannot use canonicalize_name because it has a different logic.
We also look for the raw name (without normalization) as setuptools 69 changed
the way it names .egg-link files (https://github.com/pypa/setuptools/issues/4167).
"""
return [
re.sub("[^A-Za-z0-9.]+", "-", raw_name) + ".egg-link",
f"{raw_name}.egg-link",
]
def egg_link_path_from_sys_path(raw_name: str) -> Optional[str]:
"""
Look for a .egg-link file for project name, by walking sys.path.
"""
egg_link_names = _egg_link_names(raw_name)
for path_item in sys.path:
for egg_link_name in egg_link_names:
egg_link = os.path.join(path_item, egg_link_name)
if os.path.isfile(egg_link):
return egg_link
return None
def egg_link_path_from_location(raw_name: str) -> Optional[str]:
"""
Return the path for the .egg-link file if it exists, otherwise, None.
There's 3 scenarios:
1) not in a virtualenv
try to find in site.USER_SITE, then site_packages
2) in a no-global virtualenv
try to find in site_packages
3) in a yes-global virtualenv
try to find in site_packages, then site.USER_SITE
(don't look in global location)
For #1 and #3, there could be odd cases, where there's an egg-link in 2
locations.
This method will just return the first one found.
"""
sites: List[str] = []
if running_under_virtualenv():
sites.append(site_packages)
if not virtualenv_no_global() and user_site:
sites.append(user_site)
else:
if user_site:
sites.append(user_site)
sites.append(site_packages)
egg_link_names = _egg_link_names(raw_name)
for site in sites:
for egg_link_name in egg_link_names:
egglink = os.path.join(site, egg_link_name)
if os.path.isfile(egglink):
return egglink
return None